| Anything that has mass and takes up space is a | | | | drop of oil. The number of small drop of oil that can be |
| matter. For examples, stone, wood, and concrete are | | | | separated from the big drop of oil (from burette) can |
| matter. Things, such as sound and wave are not | | | | be determined by transferring the oil from the watch |
| matter. Atomic theory of matter had been announced | | | | glass to the filter paper using sharp tip glass rod. A |
| that matter consists of fine discrete particles. These | | | | small drop of oil is adhered to the sharp tip and is |
| fine particles are discrete and existent separately | | | | transferred to the filter paper. The filter paper is a high |
| among themselves. These fine particles can exist as | | | | oil absorption material. In such a way, it can absorb |
| atom, molecule or ion. | | | | most of the oil, which adheres to the sharp tip glass |
| Atom is the smallest neutral particles in an element. | | | | rod. From the number of small drop oil that has been |
| Neutral particle is the particle that without any charge | | | | transferred to the filter paper, volume of small drop of |
| either positive or negative charge. Element is a pure | | | | oil can be calculated by dividing the volume of big drop |
| substance that contains one type of atom only. It also | | | | of oil from burette to the number of transferring. The |
| cannot be divided to simpler substances. For an | | | | calculation is as follow: |
| example, 100% pure iron block contains only iron | | | | Volume of the big drop of oil that is dripped from the |
| atoms. | | | | burette has been determined as (y-x) / 50 cm3 in the |
| Compound is formed by chemical reaction through | | | | part A. |
| association or combination of two or more elements. | | | | Volume of the small drop of oil that adheres on the |
| Chemical bond must have been formed among the | | | | sharp tip of the glass rod = volume of the big drop of |
| elements in the compound. If the elements do not form | | | | oil on the watch glass divides by the number of |
| any bond, they are only a mixture. Molecule is a neutral | | | | transferring times. Equation for the calculation is as |
| particle that is formed through chemical association or | | | | follow: |
| combination of two or more atoms either similar or | | | | Volume of the small drop of oil that adheres on the |
| different type of atom. | | | | sharp tip of the glass rod = |
| Chlorine is a molecule, which has same type of atom; | | | | (y-x)/50n |
| whereas methane is a molecule, which has different | | | | Where n = number of transferring times for the small |
| type of atom. Two chlorine atoms form bond with | | | | drop of oil from the watch glass to the filter paper. |
| each other; whereas, carbon atom in methane forms | | | | Part C: Determination the area of the oil spot on the |
| four bonds with four hydrogen atoms. | | | | surface of the water |
| Ion is a particle contains either positive or negative | | | | When a small drop of oil that adheres on the sharp tip |
| charge. It forms after the electrons in an atom or | | | | of the glass rod is dripped on the surface of the water |
| molecule have been transferred to other destination or | | | | with a thin layer of lycopodium powder covers on it, |
| from other destination into the atom or molecule. Due | | | | the oil will push the lycopodium powder to the edge of |
| to the transferring of electrons inside the atom and | | | | the tray. Diameter of the forming spot can be |
| molecule, the atom and molecule may be in | | | | measured using ruler. This value can be used to |
| unbalanced charge situation. If the atom and molecule | | | | calculate the surface area of the oil spot. The |
| are in excess of electron, they become negatively | | | | calculation is as follow: |
| charged. Contrary, if they in an electron deficiency | | | | We represent oil spot diameter as d cm. |
| situation, they become positively charge. Anion is the | | | | Surface area of the oil spot on the water surface = |
| term for the atom or molecule that is negatively | | | | surface area of a circle = j2 = (d |
| charged; whereas cation is the term for positive | | | | 2)2 cm2 |
| charge atom and molecule. Examples for the cation | | | | Part D: Estimating the size of an oil particle |
| are Mg2+, Ca2+, Na+,Fe3+ and examples for anion | | | | Size of the olive oil particle can be calculated as follow: |
| are SO42-, NO3-, PO43-, Cl- | | | | Thickness of the oil layer is represented as t cm. |
| Matter consists of fine particles that always move | | | | Volume of oil spot in the form of cylinder = |
| randomly. Evidence that can support the matter kinetic | | | | (d/2)2 t cm3 |
| theory is the diffusion process. Following is an | | | | Due to the volume of the oil spot on the surface of |
| experiment to estimate the olive oil particle size. | | | | water is equal to the volume of a small drop of oil, |
| Part A: Determination of the volume of a drop of oil | | | | which is transferred from the watch glass. Therefore, |
| Fifty drops of olive oil are dripped into the beaker from | | | | (d/2)2 t cm3 = V |
| the burette. Volume for the fifty drops of oil can be | | | | => (d2/4) t = V |
| obtained from the burette by deducting the final | | | | => t = (4V/ d2) cm |
| volume to initial volume of the burette. Volume for one | | | | By assuming oil spot on the surface of the water |
| drop of olive oil can be obtained by dividing the volume | | | | consists of only a layer of particles. So, |
| of the fifty drops of olive oil with fifty. Calculation of the | | | | Size for an oil particle, t = (4V/ d2) cm |
| volume for one drop of olive oil is as follow: | | | | Value that normally obtained is around 10-7 cm. This |
| Initial volume before dripping 50 drops of oil = x cm3 | | | | indicated that size for an oil particle is very small. |
| Final volume after dripping 50 drops of oil = y cm3 | | | | Besides, precaution steps that need to be taken in |
| Volume of 50 drops of oil = (y-x) cm3 | | | | order that the obtained result is more precise and |
| Volume for one drop of oil = (y-x) / 50 cm3 | | | | accurate are as follow: |
| Part B: Determination of the number of small drop of oil | | | | (i) Water in the tray must stable before the lycopodium |
| that can be separated from a drop of oil, which is | | | | powder is scattered on top of it. |
| dripped from the burette | | | | (ii) Layer of the lycopodium powder on the water |
| A drop of oil, which is dripped from burette, is too big | | | | surface must as thin as possible and equilibrium. |
| to drip on the surface of water with a thin layer of | | | | (iii) Tray and the water in it must be free from any oil |
| lycopodium powder covers on it. Therefore, drop of oil | | | | stain and dirt that will affect the equilibrium of the oil |
| from burette has to be separated again to a smaller | | | | spot. |